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What will be the output of the following C code?
    #include <stdio.h>
    void main()
    {
        int k = 8;
        int x = 0 == 1 && k++;
        printf("%d%d\n", x, k);
    }
  • a)
    0 9
  • b)
    0 8
  • c)
    1 8
  • d)
    1 9
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following C code? #include <stdio.h...
Explanation:

Initialization:
- The variable `k` is initialized to `8`.
- The expression `0 == 1` evaluates to `0`.

Logical AND Operator:
- In the expression `0 == 1 && k++`, the logical AND operator `&&` short-circuits if the left operand is `false` (in this case, `0`).
- Since `0` is false, the right operand `k++` is not evaluated.
- Therefore, the value of `k` remains `8`.

Printing:
- The value of `x` is the result of the logical AND operation, which is `0`.
- The value of `k` remains `8`.
- The `printf` statement prints the values of `x` and `k` which are `0` and `8` respectively.
Therefore, the output of the code will be:
0 8
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